A car traveling at 33 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration? Good Day.... Problem: A car traveling at 33 m/s starts to decelerate steadily. It comes to a complete stop in 6 seconds. What is its acceleration? Given Data: Vi (velocity initial) = 33 m/s Vf (velocity final) = 0 m/s (complete stop) t = 6 s a = ? unknown Solution: The formula in computing acceleration is acceleration = (Vf - Vi) / t acceleration = (0 m/s - 33 m/s) / 10 s = -33 m/s / 6 s = - 5.5 m/s^2 The acceleration is = - 5.5 m/s^2 (negative since the car decelerates) Hope this helps....=)
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